RegularByteTransformTransInt64 方法 (Byte, Int32, Int32, Int32) |
从缓存中提取long二维数组结果,需要指定起始的字节索引,按照字节为单位,然后指定提取的 long 数组的行和列的长度,按照 long 为单位的个数。
To extract the result of a long two-dimensional array from the cache, you need to specify the starting byte index, in bytes,
and then specify the length of the rows and columns of the extracted long array, in long as the number of units.
命名空间:
HslCommunication.Core
程序集:
HslCommunication (在 HslCommunication.dll 中) 版本:12.1.2.0 (12.1.2.0)
语法 public long[,] TransInt64(
byte[] buffer,
int index,
int row,
int col
)
Public Function TransInt64 (
buffer As Byte(),
index As Integer,
row As Integer,
col As Integer
) As Long(,)
public:
virtual array<long long,2>^ TransInt64(
array<unsigned char>^ buffer,
int index,
int row,
int col
) sealed
abstract TransInt64 :
buffer : byte[] *
index : int *
row : int *
col : int -> int64[,]
override TransInt64 :
buffer : byte[] *
index : int *
row : int *
col : int -> int64[,]
参数
- buffer
- 类型:SystemByte
缓存数据 - index
- 类型:SystemInt32
索引位置 - row
- 类型:SystemInt32
二维数组行 - col
- 类型:SystemInt32
二维数组列
返回值
类型:
Int64long二维数组对象
实现
IByteTransformTransInt64(Byte, Int32, Int32, Int32)参见